7+4(3-y)=5(y+2)

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Solution for 7+4(3-y)=5(y+2) equation: 



7+4(3-y)=5(y+2)

We move all terms to the left:

7+4(3-y)-(5(y+2))=0

We add all the numbers together, and all the variables

4(-1y+3)-(5(y+2))+7=0

We multiply parentheses

-4y-(5(y+2))+12+7=0



We calculate terms in parentheses: -(5(y+2)), so:

5(y+2)

We multiply parentheses

5y+10

Back to the equation:

-(5y+10)



We add all the numbers together, and all the variables

-4y-(5y+10)+19=0

We get rid of parentheses

-4y-5y-10+19=0

We add all the numbers together, and all the variables

-9y+9=0

We move all terms containing y to the left, all other terms to the right

-9y=-9

y=-9/-9

y=1

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