7+4(3x-4)=-17+8+12x

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Solution for 7+4(3x-4)=-17+8+12x equation:



7+4(3x-4)=-17+8+12x
We move all terms to the left:
7+4(3x-4)-(-17+8+12x)=0
We add all the numbers together, and all the variables
4(3x-4)-(12x-9)+7=0
We multiply parentheses
12x-(12x-9)-16+7=0
We get rid of parentheses
12x-12x+9-16+7=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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