7+4(5x-4)=7-5(2x+1)

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Solution for 7+4(5x-4)=7-5(2x+1) equation:



7+4(5x-4)=7-5(2x+1)
We move all terms to the left:
7+4(5x-4)-(7-5(2x+1))=0
We multiply parentheses
20x-(7-5(2x+1))-16+7=0
We calculate terms in parentheses: -(7-5(2x+1)), so:
7-5(2x+1)
determiningTheFunctionDomain -5(2x+1)+7
We multiply parentheses
-10x-5+7
We add all the numbers together, and all the variables
-10x+2
Back to the equation:
-(-10x+2)
We add all the numbers together, and all the variables
20x-(-10x+2)-9=0
We get rid of parentheses
20x+10x-2-9=0
We add all the numbers together, and all the variables
30x-11=0
We move all terms containing x to the left, all other terms to the right
30x=11
x=11/30
x=11/30

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