7+4(5x-4)=7-5(2x+1)

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Solution for 7+4(5x-4)=7-5(2x+1) equation: 



7+4(5x-4)=7-5(2x+1)

We move all terms to the left:

7+4(5x-4)-(7-5(2x+1))=0

We multiply parentheses

20x-(7-5(2x+1))-16+7=0



We calculate terms in parentheses: -(7-5(2x+1)), so:

7-5(2x+1)

determiningTheFunctionDomain
-5(2x+1)+7

We multiply parentheses

-10x-5+7

We add all the numbers together, and all the variables

-10x+2

Back to the equation:

-(-10x+2)



We add all the numbers together, and all the variables

20x-(-10x+2)-9=0

We get rid of parentheses

20x+10x-2-9=0

We add all the numbers together, and all the variables

30x-11=0

We move all terms containing x to the left, all other terms to the right

30x=11

x=11/30

x=11/30

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