7+4(t+5)=-3(2t+6)

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Solution for 7+4(t+5)=-3(2t+6) equation: 



7+4(t+5)=-3(2t+6)

We move all terms to the left:

7+4(t+5)-(-3(2t+6))=0

We multiply parentheses

4t-(-3(2t+6))+20+7=0



We calculate terms in parentheses: -(-3(2t+6)), so:

-3(2t+6)

We multiply parentheses

-6t-18

Back to the equation:

-(-6t-18)



We add all the numbers together, and all the variables

4t-(-6t-18)+27=0

We get rid of parentheses

4t+6t+18+27=0

We add all the numbers together, and all the variables

10t+45=0

We move all terms containing t to the left, all other terms to the right

10t=-45

t=-45/10

t=-4+1/2

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