7+4b=4(1+b)+3

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Solution for 7+4b=4(1+b)+3 equation: 


Simplifying
7 + 4b = 4(1 + b) + 3
7 + 4b = (1 * 4 + b * 4) + 3
7 + 4b = (4 + 4b) + 3

Reorder the terms:
7 + 4b = 4 + 3 + 4b

Combine like terms: 4 + 3 = 7
7 + 4b = 7 + 4b

Add '-7' to each side of the equation.
7 + -7 + 4b = 7 + -7 + 4b

Combine like terms: 7 + -7 = 0
0 + 4b = 7 + -7 + 4b
4b = 7 + -7 + 4b

Combine like terms: 7 + -7 = 0
4b = 0 + 4b
4b = 4b

Add '-4b' to each side of the equation.
4b + -4b = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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