If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(((4*x)/1)/2)*x+7 = 0
((4*x)/2)*x+7 = 0
2*x^2 = -7 // : 2
x^2 = -7/2
x belongs to the empty set
| 2w+2l=36 | | -5*[a-4*(2a+3)]+2=5a+2 | | 16/7=-8v | | 11a+a-3a=-7 | | -7/8y=35 | | 2+x(x)=9 | | 8*(2t-1)=5*(3t+7) | | K^2+12k+35=0 | | 5x-8y=-7 | | -33=7(y-6)+2y | | 3x+20=x^2 | | 5(X+3)-(-7+4X)=3X+16 | | (7y+6)-(5+6y)=9 | | 34=4x+2(x+5) | | 1=1.5x-1 | | 2(u-2)+7u=-13 | | -5(-3+2z)= | | -9078(27x-65)=78.24(6x+34) | | 6x-8=6+16 | | -3=7(v+6)+8v | | -22x-4x=10-8x | | 7(-2/5)+8=5.3 | | 9+-6-6+=6 | | 7x+7-9x=15-16x+14x-8 | | -7+.75b=-6 | | 7*(x-2)=34-x | | 10+8/x=2 | | x^2+10=59 | | -z+4=28 | | 5(t-3)+9=3(t-2)+6 | | -3x+12=-10x-5 | | -8+.75y=2 |