7+5(2u-3)=-2(2u-4)+2u

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Solution for 7+5(2u-3)=-2(2u-4)+2u equation: 



7+5(2u-3)=-2(2u-4)+2u

We move all terms to the left:

7+5(2u-3)-(-2(2u-4)+2u)=0

We multiply parentheses

10u-(-2(2u-4)+2u)-15+7=0



We calculate terms in parentheses: -(-2(2u-4)+2u), so:

-2(2u-4)+2u

We add all the numbers together, and all the variables

2u-2(2u-4)

We multiply parentheses

2u-4u+8

We add all the numbers together, and all the variables

-2u+8

Back to the equation:

-(-2u+8)



We add all the numbers together, and all the variables

10u-(-2u+8)-8=0

We get rid of parentheses

10u+2u-8-8=0

We add all the numbers together, and all the variables

12u-16=0

We move all terms containing u to the left, all other terms to the right

12u=16

u=16/12

u=1+1/3

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