7+5(3c-1)=15c+2

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Solution for 7+5(3c-1)=15c+2 equation:


Simplifying
7 + 5(3c + -1) = 15c + 2

Reorder the terms:
7 + 5(-1 + 3c) = 15c + 2
7 + (-1 * 5 + 3c * 5) = 15c + 2
7 + (-5 + 15c) = 15c + 2

Combine like terms: 7 + -5 = 2
2 + 15c = 15c + 2

Reorder the terms:
2 + 15c = 2 + 15c

Add '-2' to each side of the equation.
2 + -2 + 15c = 2 + -2 + 15c

Combine like terms: 2 + -2 = 0
0 + 15c = 2 + -2 + 15c
15c = 2 + -2 + 15c

Combine like terms: 2 + -2 = 0
15c = 0 + 15c
15c = 15c

Add '-15c' to each side of the equation.
15c + -15c = 15c + -15c

Combine like terms: 15c + -15c = 0
0 = 15c + -15c

Combine like terms: 15c + -15c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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