7+5(R+3)=6+3(R-2)

Solution for 7+5(R+3)=6+3(R-2) equation:

Simplifying
7 + 5(R + 3) = 6 + 3(R + -2)

Reorder the terms:
7 + 5(3 + R) = 6 + 3(R + -2)
7 + (3 * 5 + R * 5) = 6 + 3(R + -2)
7 + (15 + 5R) = 6 + 3(R + -2)

Combine like terms: 7 + 15 = 22
22 + 5R = 6 + 3(R + -2)

Reorder the terms:
22 + 5R = 6 + 3(-2 + R)
22 + 5R = 6 + (-2 * 3 + R * 3)
22 + 5R = 6 + (-6 + 3R)

Combine like terms: 6 + -6 = 0
22 + 5R = 0 + 3R
22 + 5R = 3R

Solving
22 + 5R = 3R

Solving for variable 'R'.

Move all terms containing R to the left, all other terms to the right.

Add '-3R' to each side of the equation.
22 + 5R + -3R = 3R + -3R

Combine like terms: 5R + -3R = 2R
22 + 2R = 3R + -3R

Combine like terms: 3R + -3R = 0
22 + 2R = 0

Add '-22' to each side of the equation.
22 + -22 + 2R = 0 + -22

Combine like terms: 22 + -22 = 0
0 + 2R = 0 + -22
2R = 0 + -22

Combine like terms: 0 + -22 = -22
2R = -22

Divide each side by '2'.
R = -11

Simplifying
R = -11