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7+5(x-2)=5-9(x-5)
We move all terms to the left:
7+5(x-2)-(5-9(x-5))=0
We multiply parentheses
5x-(5-9(x-5))-10+7=0
We calculate terms in parentheses: -(5-9(x-5)), so:We add all the numbers together, and all the variables
5-9(x-5)
determiningTheFunctionDomain -9(x-5)+5
We multiply parentheses
-9x+45+5
We add all the numbers together, and all the variables
-9x+50
Back to the equation:
-(-9x+50)
5x-(-9x+50)-3=0
We get rid of parentheses
5x+9x-50-3=0
We add all the numbers together, and all the variables
14x-53=0
We move all terms containing x to the left, all other terms to the right
14x=53
x=53/14
x=3+11/14