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7+5(x-3)=(x+2)
We move all terms to the left:
7+5(x-3)-((x+2))=0
We multiply parentheses
5x-((x+2))-15+7=0
We calculate terms in parentheses: -((x+2)), so:We add all the numbers together, and all the variables
(x+2)
We get rid of parentheses
x+2
Back to the equation:
-(x+2)
5x-(x+2)-8=0
We get rid of parentheses
5x-x-2-8=0
We add all the numbers together, and all the variables
4x-10=0
We move all terms containing x to the left, all other terms to the right
4x=10
x=10/4
x=2+1/2
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