7+5(x-4)=2(x+4)

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Solution for 7+5(x-4)=2(x+4) equation: 



7+5(x-4)=2(x+4)

We move all terms to the left:

7+5(x-4)-(2(x+4))=0

We multiply parentheses

5x-(2(x+4))-20+7=0



We calculate terms in parentheses: -(2(x+4)), so:

2(x+4)

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

5x-(2x+8)-13=0

We get rid of parentheses

5x-2x-8-13=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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