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7+5=x+(4x-3)
We move all terms to the left:
7+5-(x+(4x-3))=0
We add all the numbers together, and all the variables
-(x+(4x-3))+12=0
We calculate terms in parentheses: -(x+(4x-3)), so:We get rid of parentheses
x+(4x-3)
We get rid of parentheses
x+4x-3
We add all the numbers together, and all the variables
5x-3
Back to the equation:
-(5x-3)
-5x+3+12=0
We add all the numbers together, and all the variables
-5x+15=0
We move all terms containing x to the left, all other terms to the right
-5x=-15
x=-15/-5
x=+3
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