7+6(x-3)=2(2x-6)+13

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Solution for 7+6(x-3)=2(2x-6)+13 equation: 



7+6(x-3)=2(2x-6)+13

We move all terms to the left:

7+6(x-3)-(2(2x-6)+13)=0

We multiply parentheses

6x-(2(2x-6)+13)-18+7=0



We calculate terms in parentheses: -(2(2x-6)+13), so:

2(2x-6)+13

We multiply parentheses

4x-12+13

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

6x-(4x+1)-11=0

We get rid of parentheses

6x-4x-1-11=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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