7+8(n+4)=3-5(n-2)

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Solution for 7+8(n+4)=3-5(n-2) equation: 



7+8(n+4)=3-5(n-2)

We move all terms to the left:

7+8(n+4)-(3-5(n-2))=0

We multiply parentheses

8n-(3-5(n-2))+32+7=0



We calculate terms in parentheses: -(3-5(n-2)), so:

3-5(n-2)

determiningTheFunctionDomain
-5(n-2)+3

We multiply parentheses

-5n+10+3

We add all the numbers together, and all the variables

-5n+13

Back to the equation:

-(-5n+13)



We add all the numbers together, and all the variables

8n-(-5n+13)+39=0

We get rid of parentheses

8n+5n-13+39=0

We add all the numbers together, and all the variables

13n+26=0

We move all terms containing n to the left, all other terms to the right

13n=-26

n=-26/13

n=-2

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