7+x-6(2x-8)=5+6x-4(3x+20)

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Solution for 7+x-6(2x-8)=5+6x-4(3x+20) equation: 



7+x-6(2x-8)=5+6x-4(3x+20)

We move all terms to the left:

7+x-6(2x-8)-(5+6x-4(3x+20))=0

We multiply parentheses

x-12x-(5+6x-4(3x+20))+48+7=0



We calculate terms in parentheses: -(5+6x-4(3x+20)), so:

5+6x-4(3x+20)

determiningTheFunctionDomain
6x-4(3x+20)+5

We multiply parentheses

6x-12x-80+5

We add all the numbers together, and all the variables

-6x-75

Back to the equation:

-(-6x-75)



We add all the numbers together, and all the variables

-11x-(-6x-75)+55=0

We get rid of parentheses

-11x+6x+75+55=0

We add all the numbers together, and all the variables

-5x+130=0

We move all terms containing x to the left, all other terms to the right

-5x=-130

x=-130/-5

x=+26

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