7-(-3y+2)=8(3y-2)

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Solution for 7-(-3y+2)=8(3y-2) equation: 



7-(-3y+2)=8(3y-2)

We move all terms to the left:

7-(-3y+2)-(8(3y-2))=0

We get rid of parentheses

3y-(8(3y-2))-2+7=0



We calculate terms in parentheses: -(8(3y-2)), so:

8(3y-2)

We multiply parentheses

24y-16

Back to the equation:

-(24y-16)



We add all the numbers together, and all the variables

3y-(24y-16)+5=0

We get rid of parentheses

3y-24y+16+5=0

We add all the numbers together, and all the variables

-21y+21=0

We move all terms containing y to the left, all other terms to the right

-21y=-21

y=-21/-21

y=1

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