7-(-y-5)=2(y+1)

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Solution for 7-(-y-5)=2(y+1) equation: 



7-(-y-5)=2(y+1)

We move all terms to the left:

7-(-y-5)-(2(y+1))=0

We add all the numbers together, and all the variables

-(-1y-5)-(2(y+1))+7=0

We get rid of parentheses

1y-(2(y+1))+5+7=0



We calculate terms in parentheses: -(2(y+1)), so:

2(y+1)

We multiply parentheses

2y+2

Back to the equation:

-(2y+2)



We add all the numbers together, and all the variables

y-(2y+2)+12=0

We get rid of parentheses

y-2y-2+12=0

We add all the numbers together, and all the variables

-1y+10=0

We move all terms containing y to the left, all other terms to the right

-y=-10

y=-10/-1

y=+10

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