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7-(2/b)=(5/b)
We move all terms to the left:
7-(2/b)-((5/b))=0
Domain of the equation: b)!=0
b!=0/1
b!=0
b∈R
Domain of the equation: b))!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
-(+2/b)-((+5/b))+7=0
We get rid of parentheses
-2/b-((+5/b))+7=0
We calculate fractions
(-2b)/b^2+(-((+5*b)/b^2+7=0
We add all the numbers together, and all the variables
(-2b)/b^2+(-((+5b)/b^2+7=0
We calculate fractions
We do not support ebpression: b^4
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