7-(2x-4)-5(x+2)=3-2(3x+1)

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Solution for 7-(2x-4)-5(x+2)=3-2(3x+1) equation: 



7-(2x-4)-5(x+2)=3-2(3x+1)

We move all terms to the left:

7-(2x-4)-5(x+2)-(3-2(3x+1))=0

We multiply parentheses

-(2x-4)-5x-(3-2(3x+1))-10+7=0

We get rid of parentheses

-2x-5x-(3-2(3x+1))+4-10+7=0



We calculate terms in parentheses: -(3-2(3x+1)), so:

3-2(3x+1)

determiningTheFunctionDomain
-2(3x+1)+3

We multiply parentheses

-6x-2+3

We add all the numbers together, and all the variables

-6x+1

Back to the equation:

-(-6x+1)



We add all the numbers together, and all the variables

-7x-(-6x+1)+1=0

We get rid of parentheses

-7x+6x-1+1=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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