7-(3+4n)=n-4(5+2n)

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Solution for 7-(3+4n)=n-4(5+2n) equation: 



7-(3+4n)=n-4(5+2n)

We move all terms to the left:

7-(3+4n)-(n-4(5+2n))=0

We add all the numbers together, and all the variables

-(4n+3)-(n-4(2n+5))+7=0

We get rid of parentheses

-4n-(n-4(2n+5))-3+7=0



We calculate terms in parentheses: -(n-4(2n+5)), so:

n-4(2n+5)

We multiply parentheses

n-8n-20

We add all the numbers together, and all the variables

-7n-20

Back to the equation:

-(-7n-20)



We add all the numbers together, and all the variables

-4n-(-7n-20)+4=0

We get rid of parentheses

-4n+7n+20+4=0

We add all the numbers together, and all the variables

3n+24=0

We move all terms containing n to the left, all other terms to the right

3n=-24

n=-24/3

n=-8

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