7-(34+2)=4-(5u-3)

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Solution for 7-(34+2)=4-(5u-3) equation: 



7-(34+2)=4-(5u-3)

We move all terms to the left:

7-(34+2)-(4-(5u-3))=0

We add all the numbers together, and all the variables

-(4-(5u-3))+7-36=0

We add all the numbers together, and all the variables

-(4-(5u-3))-29=0



We calculate terms in parentheses: -(4-(5u-3)), so:

4-(5u-3)

determiningTheFunctionDomain
-(5u-3)+4

We get rid of parentheses

-5u+3+4

We add all the numbers together, and all the variables

-5u+7

Back to the equation:

-(-5u+7)



We get rid of parentheses

5u-7-29=0

We add all the numbers together, and all the variables

5u-36=0

We move all terms containing u to the left, all other terms to the right

5u=36

u=36/5

u=7+1/5

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