7-(3x+20)=4(x-2)

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Solution for 7-(3x+20)=4(x-2) equation: 



7-(3x+20)=4(x-2)

We move all terms to the left:

7-(3x+20)-(4(x-2))=0

We get rid of parentheses

-3x-(4(x-2))-20+7=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

-3x-(4x-8)-13=0

We get rid of parentheses

-3x-4x+8-13=0

We add all the numbers together, and all the variables

-7x-5=0

We move all terms containing x to the left, all other terms to the right

-7x=5

x=5/-7

x=-5/7

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