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7-(4+2(x-3))=(x+2)
We move all terms to the left:
7-(4+2(x-3))-((x+2))=0
We calculate terms in parentheses: -(4+2(x-3)), so:
4+2(x-3)
determiningTheFunctionDomain 2(x-3)+4
We multiply parentheses
2x-6+4
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
We calculate terms in parentheses: -((x+2)), so:We get rid of parentheses
(x+2)
We get rid of parentheses
x+2
Back to the equation:
-(x+2)
-2x-x+2-2+7=0
We add all the numbers together, and all the variables
-3x+7=0
We move all terms containing x to the left, all other terms to the right
-3x=-7
x=-7/-3
x=2+1/3
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