7-(4+x)=8x-2(3x+5)

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Solution for 7-(4+x)=8x-2(3x+5) equation: 



7-(4+x)=8x-2(3x+5)

We move all terms to the left:

7-(4+x)-(8x-2(3x+5))=0

We add all the numbers together, and all the variables

-(x+4)-(8x-2(3x+5))+7=0

We get rid of parentheses

-x-(8x-2(3x+5))-4+7=0



We calculate terms in parentheses: -(8x-2(3x+5)), so:

8x-2(3x+5)

We multiply parentheses

8x-6x-10

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

-1x-(2x-10)+3=0

We get rid of parentheses

-1x-2x+10+3=0

We add all the numbers together, and all the variables

-3x+13=0

We move all terms containing x to the left, all other terms to the right

-3x=-13

x=-13/-3

x=4+1/3

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