7-(4-3x)+3(4x-5)=-18+6x-3(-2x-5)

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Solution for 7-(4-3x)+3(4x-5)=-18+6x-3(-2x-5) equation: 



7-(4-3x)+3(4x-5)=-18+6x-3(-2x-5)

We move all terms to the left:

7-(4-3x)+3(4x-5)-(-18+6x-3(-2x-5))=0

We add all the numbers together, and all the variables

-(-3x+4)+3(4x-5)-(-18+6x-3(-2x-5))+7=0

We multiply parentheses

-(-3x+4)+12x-(-18+6x-3(-2x-5))-15+7=0

We get rid of parentheses

3x+12x-(-18+6x-3(-2x-5))-4-15+7=0



We calculate terms in parentheses: -(-18+6x-3(-2x-5)), so:

-18+6x-3(-2x-5)

determiningTheFunctionDomain
6x-3(-2x-5)-18

We multiply parentheses

6x+6x+15-18

We add all the numbers together, and all the variables

12x-3

Back to the equation:

-(12x-3)



We add all the numbers together, and all the variables

15x-(12x-3)-12=0

We get rid of parentheses

15x-12x+3-12=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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