7-(4-x)+20=5x-3(x+8)

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Solution for 7-(4-x)+20=5x-3(x+8) equation: 



7-(4-x)+20=5x-3(x+8)

We move all terms to the left:

7-(4-x)+20-(5x-3(x+8))=0

We add all the numbers together, and all the variables

-(-1x+4)-(5x-3(x+8))+7+20=0

We add all the numbers together, and all the variables

-(-1x+4)-(5x-3(x+8))+27=0

We get rid of parentheses

1x-(5x-3(x+8))-4+27=0



We calculate terms in parentheses: -(5x-3(x+8)), so:

5x-3(x+8)

We multiply parentheses

5x-3x-24

We add all the numbers together, and all the variables

2x-24

Back to the equation:

-(2x-24)



We add all the numbers together, and all the variables

x-(2x-24)+23=0

We get rid of parentheses

x-2x+24+23=0

We add all the numbers together, and all the variables

-1x+47=0

We move all terms containing x to the left, all other terms to the right

-x=-47

x=-47/-1

x=+47

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