7-(4p+3)=-3(p+2)-(2p-3)

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Solution for 7-(4p+3)=-3(p+2)-(2p-3) equation: 



7-(4p+3)=-3(p+2)-(2p-3)

We move all terms to the left:

7-(4p+3)-(-3(p+2)-(2p-3))=0

We get rid of parentheses

-4p-(-3(p+2)-(2p-3))-3+7=0



We calculate terms in parentheses: -(-3(p+2)-(2p-3)), so:

-3(p+2)-(2p-3)

We multiply parentheses

-3p-(2p-3)-6

We get rid of parentheses

-3p-2p+3-6

We add all the numbers together, and all the variables

-5p-3

Back to the equation:

-(-5p-3)



We add all the numbers together, and all the variables

-4p-(-5p-3)+4=0

We get rid of parentheses

-4p+5p+3+4=0

We add all the numbers together, and all the variables

p+7=0

We move all terms containing p to the left, all other terms to the right

p=-7

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