7-(7y+1)=8(7y-1)-(y-3)

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Solution for 7-(7y+1)=8(7y-1)-(y-3) equation: 



7-(7y+1)=8(7y-1)-(y-3)

We move all terms to the left:

7-(7y+1)-(8(7y-1)-(y-3))=0

We get rid of parentheses

-7y-(8(7y-1)-(y-3))-1+7=0



We calculate terms in parentheses: -(8(7y-1)-(y-3)), so:

8(7y-1)-(y-3)

We multiply parentheses

56y-(y-3)-8

We get rid of parentheses

56y-y+3-8

We add all the numbers together, and all the variables

55y-5

Back to the equation:

-(55y-5)



We add all the numbers together, and all the variables

-7y-(55y-5)+6=0

We get rid of parentheses

-7y-55y+5+6=0

We add all the numbers together, and all the variables

-62y+11=0

We move all terms containing y to the left, all other terms to the right

-62y=-11

y=-11/-62

y=11/62

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