7-(m-4)=-3+2(2m+1)

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Solution for 7-(m-4)=-3+2(2m+1) equation: 



7-(m-4)=-3+2(2m+1)

We move all terms to the left:

7-(m-4)-(-3+2(2m+1))=0

We get rid of parentheses

-m-(-3+2(2m+1))+4+7=0



We calculate terms in parentheses: -(-3+2(2m+1)), so:

-3+2(2m+1)

determiningTheFunctionDomain
2(2m+1)-3

We multiply parentheses

4m+2-3

We add all the numbers together, and all the variables

4m-1

Back to the equation:

-(4m-1)



We add all the numbers together, and all the variables

-1m-(4m-1)+11=0

We get rid of parentheses

-1m-4m+1+11=0

We add all the numbers together, and all the variables

-5m+12=0

We move all terms containing m to the left, all other terms to the right

-5m=-12

m=-12/-5

m=2+2/5

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