7-(x+11)+3=2(x-4)-12

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Solution for 7-(x+11)+3=2(x-4)-12 equation: 



7-(x+11)+3=2(x-4)-12

We move all terms to the left:

7-(x+11)+3-(2(x-4)-12)=0

We add all the numbers together, and all the variables

-(x+11)-(2(x-4)-12)+10=0

We get rid of parentheses

-x-(2(x-4)-12)-11+10=0



We calculate terms in parentheses: -(2(x-4)-12), so:

2(x-4)-12

We multiply parentheses

2x-8-12

We add all the numbers together, and all the variables

2x-20

Back to the equation:

-(2x-20)



We add all the numbers together, and all the variables

-1x-(2x-20)-1=0

We get rid of parentheses

-1x-2x+20-1=0

We add all the numbers together, and all the variables

-3x+19=0

We move all terms containing x to the left, all other terms to the right

-3x=-19

x=-19/-3

x=6+1/3

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