7-(y+2)=9-4(2y-1)

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Solution for 7-(y+2)=9-4(2y-1) equation: 



7-(y+2)=9-4(2y-1)

We move all terms to the left:

7-(y+2)-(9-4(2y-1))=0

We get rid of parentheses

-y-(9-4(2y-1))-2+7=0



We calculate terms in parentheses: -(9-4(2y-1)), so:

9-4(2y-1)

determiningTheFunctionDomain
-4(2y-1)+9

We multiply parentheses

-8y+4+9

We add all the numbers together, and all the variables

-8y+13

Back to the equation:

-(-8y+13)



We add all the numbers together, and all the variables

-1y-(-8y+13)+5=0

We get rid of parentheses

-1y+8y-13+5=0

We add all the numbers together, and all the variables

7y-8=0

We move all terms containing y to the left, all other terms to the right

7y=8

y=8/7

y=1+1/7

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