7-1/2(8x-3)=10-4/5(3-4x)

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Solution for 7-1/2(8x-3)=10-4/5(3-4x) equation: 



7-1/2(8x-3)=10-4/5(3-4x)

We move all terms to the left:

7-1/2(8x-3)-(10-4/5(3-4x))=0



Domain of the equation: 2(8x-3)!=0

x∈R





Domain of the equation: 5(3-4x))!=0

x∈R



We add all the numbers together, and all the variables

-1/2(8x-3)-(10-4/5(-4x+3))+7=0

We calculate fractions


(-5x(-)/(2(8x-3)*5(-4x+3)))+(-(-8x8)/(2(8x-3)*5(-4x+3)))+7=0



We calculate terms in parentheses: +(-5x(-)/(2(8x-3)*5(-4x+3))), so:

-5x(-)/(2(8x-3)*5(-4x+3))

We add all the numbers together, and all the variables

-5x0/(2(8x-3)*5(-4x+3))

We multiply all the terms by the denominator


-5x0

We add all the numbers together, and all the variables

-5x

Back to the equation:

+(-5x)





We calculate terms in parentheses: +(-(-8x8)/(2(8x-3)*5(-4x+3))), so:

-(-8x8)/(2(8x-3)*5(-4x+3))

We add all the numbers together, and all the variables

-(-8x^8)/(2(8x-3)*5(-4x+3))

We multiply all the terms by the denominator


-(-8x^8)

We do not support expression: x^8

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