7-2(3x+5)-(2x-3)=-5(x+1)-2(x-4)

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Solution for 7-2(3x+5)-(2x-3)=-5(x+1)-2(x-4) equation: 



7-2(3x+5)-(2x-3)=-5(x+1)-2(x-4)

We move all terms to the left:

7-2(3x+5)-(2x-3)-(-5(x+1)-2(x-4))=0

We multiply parentheses

-6x-(2x-3)-(-5(x+1)-2(x-4))-10+7=0

We get rid of parentheses

-6x-2x-(-5(x+1)-2(x-4))+3-10+7=0



We calculate terms in parentheses: -(-5(x+1)-2(x-4)), so:

-5(x+1)-2(x-4)

We multiply parentheses

-5x-2x-5+8

We add all the numbers together, and all the variables

-7x+3

Back to the equation:

-(-7x+3)



We add all the numbers together, and all the variables

-8x-(-7x+3)=0

We get rid of parentheses

-8x+7x-3=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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