7-2(3x-3)=4x-(2-3x)

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Solution for 7-2(3x-3)=4x-(2-3x) equation: 



7-2(3x-3)=4x-(2-3x)

We move all terms to the left:

7-2(3x-3)-(4x-(2-3x))=0

We add all the numbers together, and all the variables

-2(3x-3)-(4x-(-3x+2))+7=0

We multiply parentheses

-6x-(4x-(-3x+2))+6+7=0



We calculate terms in parentheses: -(4x-(-3x+2)), so:

4x-(-3x+2)

We get rid of parentheses

4x+3x-2

We add all the numbers together, and all the variables

7x-2

Back to the equation:

-(7x-2)



We add all the numbers together, and all the variables

-6x-(7x-2)+13=0

We get rid of parentheses

-6x-7x+2+13=0

We add all the numbers together, and all the variables

-13x+15=0

We move all terms containing x to the left, all other terms to the right

-13x=-15

x=-15/-13

x=1+2/13

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