7-2(3x-8)+11=48

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Solution for 7-2(3x-8)+11=48 equation: 



7-2(3x-8)+11=48

We move all terms to the left:

7-2(3x-8)+11-(48)=0

We add all the numbers together, and all the variables

-2(3x-8)-30=0

We multiply parentheses

-6x+16-30=0

We add all the numbers together, and all the variables

-6x-14=0

We move all terms containing x to the left, all other terms to the right

-6x=14

x=14/-6

x=-2+1/3

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