7-2(4-3x)=4(x+2)+2x-3

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Solution for 7-2(4-3x)=4(x+2)+2x-3 equation: 



7-2(4-3x)=4(x+2)+2x-3

We move all terms to the left:

7-2(4-3x)-(4(x+2)+2x-3)=0

We add all the numbers together, and all the variables

-2(-3x+4)-(4(x+2)+2x-3)+7=0

We multiply parentheses

6x-(4(x+2)+2x-3)-8+7=0



We calculate terms in parentheses: -(4(x+2)+2x-3), so:

4(x+2)+2x-3

We add all the numbers together, and all the variables

2x+4(x+2)-3

We multiply parentheses

2x+4x+8-3

We add all the numbers together, and all the variables

6x+5

Back to the equation:

-(6x+5)



We add all the numbers together, and all the variables

6x-(6x+5)-1=0

We get rid of parentheses

6x-6x-5-1=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation

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