7-2(4j-3)=-3

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Solution for 7-2(4j-3)=-3 equation: 



7-2(4j-3)=-3

We move all terms to the left:

7-2(4j-3)-(-3)=0

We add all the numbers together, and all the variables

-2(4j-3)+10=0

We multiply parentheses

-8j+6+10=0

We add all the numbers together, and all the variables

-8j+16=0

We move all terms containing j to the left, all other terms to the right

-8j=-16

j=-16/-8

j=+2

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