7-2(5x-3)+7x=8x-2(1+3x)

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Solution for 7-2(5x-3)+7x=8x-2(1+3x) equation: 



7-2(5x-3)+7x=8x-2(1+3x)

We move all terms to the left:

7-2(5x-3)+7x-(8x-2(1+3x))=0

We add all the numbers together, and all the variables

-2(5x-3)+7x-(8x-2(3x+1))+7=0

We add all the numbers together, and all the variables

7x-2(5x-3)-(8x-2(3x+1))+7=0

We multiply parentheses

7x-10x-(8x-2(3x+1))+6+7=0



We calculate terms in parentheses: -(8x-2(3x+1)), so:

8x-2(3x+1)

We multiply parentheses

8x-6x-2

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

-3x-(2x-2)+13=0

We get rid of parentheses

-3x-2x+2+13=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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