7-2(6-3y)=4(y-2)-6

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Solution for 7-2(6-3y)=4(y-2)-6 equation:



7-2(6-3y)=4(y-2)-6
We move all terms to the left:
7-2(6-3y)-(4(y-2)-6)=0
We add all the numbers together, and all the variables
-2(-3y+6)-(4(y-2)-6)+7=0
We multiply parentheses
6y-(4(y-2)-6)-12+7=0
We calculate terms in parentheses: -(4(y-2)-6), so:
4(y-2)-6
We multiply parentheses
4y-8-6
We add all the numbers together, and all the variables
4y-14
Back to the equation:
-(4y-14)
We add all the numbers together, and all the variables
6y-(4y-14)-5=0
We get rid of parentheses
6y-4y+14-5=0
We add all the numbers together, and all the variables
2y+9=0
We move all terms containing y to the left, all other terms to the right
2y=-9
y=-9/2
y=-4+1/2

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