7-2(m-4)+7m=-3m+16-m

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Solution for 7-2(m-4)+7m=-3m+16-m equation: 



7-2(m-4)+7m=-3m+16-m

We move all terms to the left:

7-2(m-4)+7m-(-3m+16-m)=0

We add all the numbers together, and all the variables

-2(m-4)+7m-(-4m+16)+7=0

We add all the numbers together, and all the variables

7m-2(m-4)-(-4m+16)+7=0

We multiply parentheses

7m-2m-(-4m+16)+8+7=0

We get rid of parentheses

7m-2m+4m-16+8+7=0

We add all the numbers together, and all the variables

9m-1=0

We move all terms containing m to the left, all other terms to the right

9m=1

m=1/9

m=1/9

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