7-2(x+1)-3(x-2)=(4-3x)2-4

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Solution for 7-2(x+1)-3(x-2)=(4-3x)2-4 equation: 



7-2(x+1)-3(x-2)=(4-3x)2-4

We move all terms to the left:

7-2(x+1)-3(x-2)-((4-3x)2-4)=0

We add all the numbers together, and all the variables

-2(x+1)-3(x-2)-((-3x+4)2-4)+7=0

We multiply parentheses

-2x-3x-((-3x+4)2-4)-2+6+7=0



We calculate terms in parentheses: -((-3x+4)2-4), so:

(-3x+4)2-4

We multiply parentheses

-6x+8-4

We add all the numbers together, and all the variables

-6x+4

Back to the equation:

-(-6x+4)



We add all the numbers together, and all the variables

-5x-(-6x+4)+11=0

We get rid of parentheses

-5x+6x-4+11=0

We add all the numbers together, and all the variables

x+7=0

We move all terms containing x to the left, all other terms to the right

x=-7

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