7-2(x+1)=3(2x-1)+2

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Solution for 7-2(x+1)=3(2x-1)+2 equation: 



7-2(x+1)=3(2x-1)+2

We move all terms to the left:

7-2(x+1)-(3(2x-1)+2)=0

We multiply parentheses

-2x-(3(2x-1)+2)-2+7=0



We calculate terms in parentheses: -(3(2x-1)+2), so:

3(2x-1)+2

We multiply parentheses

6x-3+2

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We add all the numbers together, and all the variables

-2x-(6x-1)+5=0

We get rid of parentheses

-2x-6x+1+5=0

We add all the numbers together, and all the variables

-8x+6=0

We move all terms containing x to the left, all other terms to the right

-8x=-6

x=-6/-8

x=3/4

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