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7-2(x+1)=3(2x-1)+2
We move all terms to the left:
7-2(x+1)-(3(2x-1)+2)=0
We multiply parentheses
-2x-(3(2x-1)+2)-2+7=0
We calculate terms in parentheses: -(3(2x-1)+2), so:We add all the numbers together, and all the variables
3(2x-1)+2
We multiply parentheses
6x-3+2
We add all the numbers together, and all the variables
6x-1
Back to the equation:
-(6x-1)
-2x-(6x-1)+5=0
We get rid of parentheses
-2x-6x+1+5=0
We add all the numbers together, and all the variables
-8x+6=0
We move all terms containing x to the left, all other terms to the right
-8x=-6
x=-6/-8
x=3/4
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