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7-2(x+3)=3(x-3)
We move all terms to the left:
7-2(x+3)-(3(x-3))=0
We multiply parentheses
-2x-(3(x-3))-6+7=0
We calculate terms in parentheses: -(3(x-3)), so:We add all the numbers together, and all the variables
3(x-3)
We multiply parentheses
3x-9
Back to the equation:
-(3x-9)
-2x-(3x-9)+1=0
We get rid of parentheses
-2x-3x+9+1=0
We add all the numbers together, and all the variables
-5x+10=0
We move all terms containing x to the left, all other terms to the right
-5x=-10
x=-10/-5
x=+2
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