7-22(3x-5)=2+3(4x-7)

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Solution for 7-22(3x-5)=2+3(4x-7) equation: 



7-22(3x-5)=2+3(4x-7)

We move all terms to the left:

7-22(3x-5)-(2+3(4x-7))=0

We multiply parentheses

-66x-(2+3(4x-7))+110+7=0



We calculate terms in parentheses: -(2+3(4x-7)), so:

2+3(4x-7)

determiningTheFunctionDomain
3(4x-7)+2

We multiply parentheses

12x-21+2

We add all the numbers together, and all the variables

12x-19

Back to the equation:

-(12x-19)



We add all the numbers together, and all the variables

-66x-(12x-19)+117=0

We get rid of parentheses

-66x-12x+19+117=0

We add all the numbers together, and all the variables

-78x+136=0

We move all terms containing x to the left, all other terms to the right

-78x=-136

x=-136/-78

x=1+29/39

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