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7-2=2/5(x+5)
We move all terms to the left:
7-2-(2/5(x+5))=0
Domain of the equation: 5(x+5))!=0We add all the numbers together, and all the variables
x∈R
-(2/5(x+5))+5=0
We multiply all the terms by the denominator
-(2+5*5(x+5))=0
We calculate terms in parentheses: -(2+5*5(x+5)), so:
2+5*5(x+5)
determiningTheFunctionDomain 5*5(x+5)+2
Wy multiply elements
25x(x+2
Back to the equation:
-(25x(x+2)
We calculate terms in parentheses: -(25x(x+2), so:
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| 6x=6=42 | | 2m+10=6m+2 | | -4x-15=9-2x | | 12=3t/4+6 | | 4x+2x+7=3x+25 | | 2(x-2)+3=2(x+1)+1 | | 0=(x-2)^2((2x-1)/(2x+1)) | | 7.7=k(30.0)^3 | | 3x/2x=-24 | | 90=5(t+8) | | x^2+(x+3)^2=15^2 | | -2p=9−3p | | 4(6x+3)=12(2x+1) | | 4(2x/8x)=0 | | 20+6q=68 | | -34+5x=39-2x | | p-6/7=2 | | 4(2x/3)=0 | | h/4+98=128 | | -1+6x=x+9 | | 2q^2-4q-16=0 | | 7−-2g=-3 | | 4(k+5)=72 | | 5(4x–2)=2(2x+19) | | |4r+7|=43 | | 8y=y+63 | | 3(x+2)-8=19 | | -2+-4u=-10 | | 37-1(2c+3)=4(1c+5)+1c | | 2x-15=4x-3=180 | | 3x-6=273 | | -3j+21=90 |