7-3(2p+1)=5-2(p+2)

Solution for 7-3(2p+1)=5-2(p+2) equation:

7-3(2p+1)=5-2(p+2)

We move all terms to the left:

7-3(2p+1)-(5-2(p+2))=0

We multiply parentheses

-6p-(5-2(p+2))-3+7=0


We calculate terms in parentheses: -(5-2(p+2)), so:

5-2(p+2)

determiningTheFunctionDomain
-2(p+2)+5

We multiply parentheses

-2p-4+5

We add all the numbers together, and all the variables

-2p+1

Back to the equation:

-(-2p+1)


We add all the numbers together, and all the variables

-6p-(-2p+1)+4=0

We get rid of parentheses

-6p+2p-1+4=0

We add all the numbers together, and all the variables

-4p+3=0

We move all terms containing p to the left, all other terms to the right

-4p=-3

p=-3/-4

p=3/4