7-3(2x+4)=6(x-2)+3

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Solution for 7-3(2x+4)=6(x-2)+3 equation: 



7-3(2x+4)=6(x-2)+3

We move all terms to the left:

7-3(2x+4)-(6(x-2)+3)=0

We multiply parentheses

-6x-(6(x-2)+3)-12+7=0



We calculate terms in parentheses: -(6(x-2)+3), so:

6(x-2)+3

We multiply parentheses

6x-12+3

We add all the numbers together, and all the variables

6x-9

Back to the equation:

-(6x-9)



We add all the numbers together, and all the variables

-6x-(6x-9)-5=0

We get rid of parentheses

-6x-6x+9-5=0

We add all the numbers together, and all the variables

-12x+4=0

We move all terms containing x to the left, all other terms to the right

-12x=-4

x=-4/-12

x=1/3

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