7-3(5-u)=5(u-4)

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Solution for 7-3(5-u)=5(u-4) equation: 



7-3(5-u)=5(u-4)

We move all terms to the left:

7-3(5-u)-(5(u-4))=0

We add all the numbers together, and all the variables

-3(-1u+5)-(5(u-4))+7=0

We multiply parentheses

3u-(5(u-4))-15+7=0



We calculate terms in parentheses: -(5(u-4)), so:

5(u-4)

We multiply parentheses

5u-20

Back to the equation:

-(5u-20)



We add all the numbers together, and all the variables

3u-(5u-20)-8=0

We get rid of parentheses

3u-5u+20-8=0

We add all the numbers together, and all the variables

-2u+12=0

We move all terms containing u to the left, all other terms to the right

-2u=-12

u=-12/-2

u=+6

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