7-3(b-1)=8+3(b-4)

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Solution for 7-3(b-1)=8+3(b-4) equation: 



7-3(b-1)=8+3(b-4)

We move all terms to the left:

7-3(b-1)-(8+3(b-4))=0

We multiply parentheses

-3b-(8+3(b-4))+3+7=0



We calculate terms in parentheses: -(8+3(b-4)), so:

8+3(b-4)

determiningTheFunctionDomain
3(b-4)+8

We multiply parentheses

3b-12+8

We add all the numbers together, and all the variables

3b-4

Back to the equation:

-(3b-4)



We add all the numbers together, and all the variables

-3b-(3b-4)+10=0

We get rid of parentheses

-3b-3b+4+10=0

We add all the numbers together, and all the variables

-6b+14=0

We move all terms containing b to the left, all other terms to the right

-6b=-14

b=-14/-6

b=2+1/3

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